I don't understand this question AT ALL.
The length of a rectangle is 5 meters greater than the width. The perimeter is 150 meters. Find the length and width of the rectangle.
It means the length is 5 meters > the width or w + 5 = l
The perimeter (distance around the rectangle) is w+w+l+l= 150
Plug in w+5 for each l and solve for w, then l.
Post your work if you get stuck.
This really did not help me a lot. Well it did not help me at all.
this didn't really help maybe u should show step by step work
To understand and solve this question, let's break it down step by step.
1. Let's start by assigning variables to the unknowns. In this case, let's use:
- Width (W) for the unknown width of the rectangle
- Length (L) for the unknown length of the rectangle
2. From the given information, we can establish two equations:
- Equation 1: L = W + 5 (The length is 5 meters greater than the width)
- Equation 2: 2(L + W) = 150 (The perimeter is 150 meters)
3. Now we have a system of two equations with two variables. We can solve these equations simultaneously to find the values of length and width.
Starting with Equation 1, we substitute L with (W + 5):
W + 5 = W + 5
Simplifying, we find:
0 = 0
Equation 1 does not provide any new information since it simplifies to a true statement. This implies that Equation 1 is dependent on Equation 2, meaning it is not a separate equation.
4. Let us proceed with Equation 2 since it contains relevant information.
2(L + W) = 150
Expanding the equation, we have:
2L + 2W = 150
Dividing by 2 to simplify, we get:
L + W = 75
Now we have a new equation that relates the length and width of the rectangle.
5. We can rewrite this equation using Equation 1 to substitute L:
(W + 5) + W = 75
Simplifying further:
2W + 5 = 75
Subtracting 5 from both sides, we have:
2W = 70
Finally, dividing both sides by 2, we find:
W = 35
6. Now that we know the width (W = 35), we can substitute this value back into any of the equations. Let's use Equation 1:
L = W + 5
L = 35 + 5
L = 40
Therefore, the length of the rectangle is 40 meters, and the width is 35 meters.