This problem concerns a student that is attempting Newton's 2nd Law, but the cart does not run without friction.
How do I calculate the drag force, givin the mass of the cart (7.6kg), the mass of the load (4.2kg), and the resulting acceleration (1.2m/s2)?
I'd appreciate the help.
I am uncertain what is making the cart move? Is is gravity? If it is gravity, and going down a ramp, you can write the equation governing motion
forcegravitydownramp- forcefriction=ma
so resolve the mg into two comonents, down the ramp, and normal to the ramp, and the solution follows.
I cant give more details without exact situation.
There is no ramp involved... its just a cart on a flat table, and then a puly, and a load. Would gravity be pulling the load down, which would make the cart move? I still don't get how I would calculate the 'drag' (friction and air resistance) force.
Here's my attempt at drawing it.
_____Cart______Pully
|
|
Load
I'm sorry, I'm just a little confused and for some reason, physics doesn't click in my head.
The "load " is the moving force.
totalmass*acceleration= loadforce-friction
frictionforce= loadfriction - totalmass*acceleration
What is the me of a 6 kg mass at 4 m/a
To calculate the drag force in this scenario, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.
The first step is to calculate the total mass of the system, including both the cart and the load. We do this by adding the masses together: 7.6 kg (cart) + 4.2 kg (load) = 11.8 kg (total mass).
Next, we need to determine the net force acting on the system. Since the only force acting on the system is the drag force, it must be equal to the mass multiplied by the acceleration. So, the net force (F_net) = total mass (m) × acceleration (a) = 11.8 kg × 1.2 m/s^2 = 14.16 N.
Finally, since the net force is equal to the drag force, the drag force (F_drag) = 14.16 N.
Therefore, the drag force acting on the system in this case is 14.16 N.