x^2 +16x+64
x^2+16x=64
(x=3)^2=16x-64
16x=-64
x=-4
Check this problem please
The first line is not an equation.
The second line is
x^2+16x=64
then if you are completing the square
x^2 + 16 x + 8^2 = 64 + 8^2
(x+8)^2 = 128
x+8 = +/- 8 sqrt 2
so
x = -8 +/- 8 sqrt 2 = 8 (-1 +/- sqrt 2)
or if you really mean
x^2 + 16 x + 64 = 0
then
x^2 + 16 x = -64
x^2 + 16 x + 64 = -64 + 64 = 0
(x+8)^2=0
x+8 = +/- 0
x = -8
Is where the following trinomials perfect squares.
X^2+16x+64 this is the problem is does not have equal. so could you work this for me please.
Oh !!!
(x+8)(x+8)
(x+8)^2 = x^2 + 16 x + 64
In other words it is not an equation and you do not solve for x.
The trinomial is the perfect square of (x+8)
for any x
To check if the solution x = -4 is correct for the equation x^2 + 16x + 64 = 0, you can substitute x=-4 back into the original equation and see if it satisfies the equation.
Original equation: x^2 + 16x + 64 = 0
Substituting x = -4 into the equation:
(-4)^2 + 16(-4) + 64 = 0
16 - 64 + 64 = 0
0 = 0
Since 0 = 0, the solution x = -4 satisfies the equation. Thus, the solution is correct.
Alternatively, to solve the equation x^2 + 16x + 64 = 0, you can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
For the equation x^2 + 16x + 64 = 0, the coefficients are:
a = 1, b = 16, c = 64
Plugging the values into the quadratic formula:
x = (-16 ± √(16^2 - 4(1)(64))) / (2(1))
Simplifying:
x = (-16 ± √(256 - 256)) / 2
x = (-16 ± √0) / 2
x = -16 / 2
x = -8
Therefore, the equation x^2 + 16x + 64 = 0 has a single solution x = -8.