An object starts from rest and accelerates at a rate of 2.50 m/s/s for 7.00 seconds. The velocity at the end of the 7.00 seconds is...
To find the velocity at the end of the 7.00 seconds, we can use the equation:
velocity = initial velocity + (acceleration * time)
Given:
Initial velocity (u) = 0 m/s (as the object starts from rest)
Acceleration (a) = 2.50 m/s/s
Time (t) = 7.00 seconds
Applying the values in the equation:
velocity = 0 + (2.50 * 7.00)
= 0 + 17.50
= 17.50 m/s
Therefore, the velocity at the end of the 7.00 seconds is 17.50 m/s.
To find the velocity at the end of the 7.00 seconds, we can use the equation for constant acceleration:
v = u + at
Where:
v is the final velocity,
u is the initial velocity (which is 0 in this case since the object starts from rest),
a is the acceleration, and
t is the time.
Given:
u = 0 m/s (initial velocity)
a = 2.50 m/s/s (acceleration)
t = 7.00 s (time)
Substituting the values into the equation:
v = 0 + (2.50)(7.00)
v = 0 + 17.50
v = 17.50 m/s
Therefore, the velocity at the end of the 7.00 seconds is 17.50 m/s.
V = a t
when the initial velocity is zero.