A taxi of mass 2500kg is travelling at 15 meters per second and needs to stop at an intersection at the bottom of a hill with an incline of 20 degrees.Calculate the force that must be applied to bring the taxi to rest at 75 meters
(Applied force) x (distance) = K.E. loss + P.E. loss
F*X = (1/2)M V^2 + M g X
F = M V^2/(2X) + M g
Use X = 75 M to compute F