Question

Trying to formulate zinc shulphate mono hydrate fro zinc ash 60%zn .using sulphuric acid as leaching agent how much zinc shulphate 32%monohydrate can I get from 1 ton of zinc ash

Answer 1

[AI-generated answer — Bot GPT 3.5]

To calculate the amount of zinc sulfate monohydrate that can be obtained from 1 ton of zinc ash with 60% zinc content, you first need to determine the amount of zinc present in the zinc ash.

1 ton = 1000 kg

Zinc content in zinc ash = 60% of 1000 kg = 600 kg

Next, calculate the molar mass of zinc sulfate to determine the stoichiometry of the reaction:

Zinc sulfate (ZnSO4) molar mass = 65.38 g/mol (Zn) + 32.06 g/mol (S) + 4 * 16.00 g/mol (O) = 161.38 g/mol

The balanced chemical equation for the reaction of zinc ash (Zn) with sulfuric acid (H2SO4) to form zinc sulfate monohydrate (ZnSO4.H2O) is:

Zn + H2SO4 → ZnSO4 + H2

From the stoichiometry of the reaction, 1 mole of zinc (Zn) reacts with 1 mole of sulfuric acid (H2SO4) to form 1 mole of zinc sulfate (ZnSO4). This means that 1 mole of zinc ash (60% Zn) can produce 1 mole of zinc sulfate.

Next, calculate the number of moles of zinc sulfate that can be obtained from 600 kg of zinc in zinc ash:

Number of moles of Zn = 600 kg / 65.38 g/mol = 9175.95 moles (approximately)

Since 1 mole of zinc ash produces 1 mole of zinc sulfate, the number of moles of zinc sulfate produced is also 9175.95 moles.

Now, calculate the mass of zinc sulfate monohydrate (32%) that can be obtained from the number of moles calculated above:

Mass of 32% zinc sulfate monohydrate = 9175.95 moles * 161.38 g/mol * 0.32 = 470,381.44 g

Convert the mass to kilograms:

Mass of 32% zinc sulfate monohydrate = 470.38 kg

Therefore, from 1 ton of zinc ash with 60% zinc content, you can obtain approximately 470.38 kg of zinc sulfate monohydrate with 32% purity.