Find the sum of the following arithmetic series:
44p+99+14+19+...plus+6969.
To find the sum of an arithmetic series, we use the formula:
Sn = n/2(2a + (n-1)d)
where Sn is the sum of the first n terms of the series, a is the first term, n is the number of terms, and d is the common difference.
In this case, a = 44p + 99, d = 14 - 19 = -5, and the last term is 6969. To find the number of terms (n), we need to find the value of p.
The last term of the series is a + (n-1)d = 6969
44p + 99 + (n-1)(-5) = 6969
44p + 99 - 5n + 5 = 6969
44p + 104 - 5n = 6969
44p - 5n = 6865
Since we can't solve for the exact values of p and n without additional information, we'll use the formula and represent the sum as:
Sn = n/2(2(44p + 99) + (n-1)(-5))
Sn = n(88p + 198 - 5n)/2
As previously stated, we can't give a numerical value for the sum without knowing the exact values of p and n.