Let f(x) = x2+7 and g(x) = x+3x . Find (g ∘ f)(−5)

First, find f(-5):

f(-5) = (-5)^2 + 7
f(-5) = 25 + 7
f(-5) = 32

Next, find g(x) when x = 32:
g(32) = 32 + 3(32)
g(32) = 32 + 96
g(32) = 128

Therefore, (g ∘ f)(-5) = g(f(-5)) = g(32) = 128.