Ryan has a pack of 10 pens. 3 pens are red, 4 are black, and 3 are blue. What are the chances that he pulls out a red pen and a black pen? Assume that the pens are pulled without replacement. Round to the nearest whole number.(1 point)
To find the probability of Ryan pulling out a red pen and a black pen, we need to calculate the probability of each event happening separately and then multiply them together.
The probability of pulling out a red pen on the first draw is 3/10.
After pulling out a red pen, there will be 9 pens left in the pack, with 4 black pens. So the probability of pulling out a black pen on the second draw is 4/9.
Therefore, the overall probability is (3/10) * (4/9) = 12/90 = 2/15 ≈ 0.1333
Rounded to the nearest whole number, the chances are 13%.