Posted by hellogoodbie on Saturday, January 16, 2010 at 3:24pm.
Posted by hellogoodbie on Saturday, January 16, 2010 at 2:59pm.
How is this problem done?
IF f(x)=2x^2-8x-3 FIND f(-2)
algebra 2 - bobpursley, Saturday, January 16, 2010 at 1:42pm
Put in for x the value -2, and compute f(-2)
algebra 2 - hellogoodbie, Saturday, January 16, 2010 at 1:47pm
so is the answer f=21/2? if that is right, thank you bobpursley
algebra 2 - drwls, Saturday, January 16, 2010 at 3:02pm
The answer has to be an integer. In this case, it is 2*4 - 8*(-2) - 3 = 21
algebra 2 - hellogoodbie, Saturday, January 16, 2010 at 3:06pm
where did u get the 4 from?
algebra 2 - bobpursley, Saturday, January 16, 2010 at 3:45pm
The four came from (x2)
two squared is 4
algebra 2 - hellogoodbie, Saturday, January 16, 2010 at 3:49pm
Wow, I'm so confused. Can somebody just solve this problem step by step please?
We just did.
X+2 = 3 - 5
X + 2 = - 2
Is mc022-1.jpg a factor of mc022-2.jpg? If it is, write mc022-3.jpg as a product of two factors.
To solve the problem, you are given the function f(x) = 2x^2 - 8x - 3 and you need to find f(-2).
Step 1: Replace every x in the function with -2.
f(-2) = 2(-2)^2 - 8(-2) - 3
Step 2: Simplify the expression.
f(-2) = 2(4) + 16 - 3
f(-2) = 8 + 16 - 3
f(-2) = 21
Therefore, f(-2) = 21.