What is the sum of the absolute deviations in the following dataset: 63, 25, 74, 52, 63, 12, 46? The mean of the dataset is 47.9. Round to the nearest tenth
To find the sum of the absolute deviations, we first need to calculate the absolute deviation of each data point from the mean, and then sum them up.
Absolute deviation of each data point:
|63-47.9| = 15.1
|25-47.9| = 22.9
|74-47.9| = 26.1
|52-47.9| = 4.1
|63-47.9| = 15.1
|12-47.9| = 35.9
|46-47.9| = 1.9
Sum of the absolute deviations:
15.1 + 22.9 + 26.1 + 4.1 + 15.1 + 35.9 + 1.9 = 121.1
Therefore, the sum of the absolute deviations in the dataset is 121.1. Round to the nearest tenth, the sum is 121.1.