In a chemical reaction, 4 mol of NO and 2.5 mol of oxygen are mixed together in in a container with volume of 1000 ml to produce NO2.if the kc for this reaction is 0.001.determine the equilibrium concentration for each substance?
The equilibrium constant expression for the reaction is:
Kc = [NO2] / ([NO]^2 * [O2])
Since initially, 4 mol of NO and 2.5 mol of O2 are mixed in a 1000 ml container, the initial concentration of NO is:
[NO] = 4 mol / 1000 ml = 0.004 mol/ml
And the initial concentration of O2 is:
[O2] = 2.5 mol / 1000 ml = 0.0025 mol/ml
Let x be the change in concentration of NO and O2 at equilibrium. Therefore, at equilibrium, the concentrations will be:
[NO] = 0.004 - 2x
[O2] = 0.0025 - x
[NO2] = x
Substitute these equilibrium concentrations into the equilibrium constant expression, we get:
0.001 = x / ((0.004 - 2x) * (0.0025 - x))
Solving for x, we get x = 0.0002 mol/ml
Therefore, at equilibrium:
[NO] = 0.004 - 2(0.0002) = 0.0036 mol/ml
[O2] = 0.0025 - 0.0002 = 0.0023 mol/ml
[NO2] = 0.0002 mol/ml
So, the equilibrium concentrations for each substance are:
[NO] = 0.0036 mol/ml
[O2] = 0.0023 mol/ml
[NO2] = 0.0002 mol/ml