Find the slope of a line parallel to the line whose equation is 3, x, minus, y, equals, minus, 13x−y=−1. Fully simplify your answer.
To find the slope of a line parallel to the given line, we first need to determine the slope of the given line. The equation of the given line is in the form of \(y = mx + b\), where m is the slope.
So, let's rearrange the given equation \(3x-y=-1\) into the form y = mx + b:
\(3x - y = -1\)
\(y = 3x + 1\)
Thus, the slope of the given line is 3.
Since we want to find the slope of a line parallel to this line, the slope of the parallel line will also be 3.
So, the slope of a line parallel to the line whose equation is \(3x - y = -1\) is 3.