Solve the system of equations.
8x−3y= −22
y=10+4x (
First, substitute the value of y from the second equation into the first equation:
8x - 3(10+4x) = -22
8x - 30 - 12x = -22
-4x - 30 = -22
-4x = 8
x = -2
Now, substitute the value of x back into the second equation to find y:
y = 10 + 4(-2)
y = 10 - 8
y = 2
Therefore, the solution to the system of equations is x = -2 and y = 2.