Suppose a family replaces ten 60-watt (0.06 kW) incandescent bulbs with ten 30-watt (0.03 kW) fluorescent bulbs. If each bulb was used for 4 hours per day and the cost of electricity was 10.0 ¢/kWh, how much money would they save in a year?(2 points) Responses explain why
$36.50
$7.30
$73.00
$365.00
$3.65
$730.00
To calculate the savings in a year, we first need to find the energy consumption per year for both incandescent and fluorescent bulbs.
Energy consumed per day by incandescent bulbs:
10 bulbs x 0.06 kW per bulb x 4 hours = 2.4 kWh
Energy consumed per year by incandescent bulbs:
2.4 kWh x 365 days = 876 kWh
Energy consumed per day by fluorescent bulbs:
10 bulbs x 0.03 kW per bulb x 4 hours = 1.2 kWh
Energy consumed per year by fluorescent bulbs:
1.2 kWh x 365 days = 438 kWh
Now, we can find the cost savings:
Cost of electricity for incandescent bulbs per year:
876 kWh x $0.10/kWh = $87.60
Cost of electricity for fluorescent bulbs per year:
438 kWh x $0.10/kWh = $43.80
Therefore, the savings in a year would be:
$87.60 - $43.80 = $43.80
The closest option to the calculated savings is $36.50, but the actual savings would be $43.80. So, none of the provided options are accurate.