Area of a rhombus is 25cm² and one of the diagonal is double the other in length find the sum of the two diagonals
Let the smaller diagonal be x cm. Then the larger diagonal would be 2x cm because it is double the length of the smaller diagonal.
The area of a rhombus can be calculated using the formula:
Area = (d1 * d2) / 2
where d1 and d2 are the diagonals of the rhombus.
Given that the area is 25 cm², we have:
25 = (x * 2x) / 2
25 = 2x^2 / 2
25 = x^2
x^2 = 25
x = 5
So, the smaller diagonal is 5 cm and the larger diagonal is 10 cm.
To find the sum of the two diagonals:
Sum = 5 + 10
Sum = 15
Therefore, the sum of the two diagonals is 15 cm.