Kamore place 7mol of ammonia in 14L flask, at equilibrium 0.2 molarity of ammonium formed.write the balance chemical equation and calculate its equilibrium constant?
The balanced chemical equation for the reaction of ammonia (NH3) forming ammonium (NH4^+) ion is:
NH3 (g) + H2O (l) ⇌ NH4^+ (aq) + OH^- (aq)
Given that 7 mol of ammonia is placed in a 14L flask, we can calculate the initial molarity of ammonia:
Initial molarity of NH3 = 7 mol / 14 L = 0.5 M
At equilibrium, 0.2 M of ammonium ion is formed. Using the stoichiometry of the reaction, we can see that the concentration of ammonium ion at equilibrium is equal to the concentration of ammonia:
[NH4^+] = 0.2 M
From the equation, we know that the concentration of hydroxide ion (OH^-) at equilibrium is also equal to the concentration of ammonia:
[OH^-] = 0.5 M
To calculate the equilibrium constant (K) for the reaction, we can use the formula:
K = [NH4^+] * [OH^-] / [NH3]
Plugging in the values, we get:
K = (0.2) * (0.5) / (0.5) = 0.2
Therefore, the equilibrium constant for the reaction is 0.2.