Use the table to answer the question.
Plant Types A B C D E
Number of Seedlings 100 140 80 60 40
A farmer conducted an inventory on his two square kilometers of rainforest; the results are in the table. He plans on randomly selecting a seedling to experiment on when he goes back to the forest. What is the probability that he will randomly pick a type B plant? Write your answer in the simplest form of a fraction.
(1 point)
The total number of seedlings is 100 + 140 + 80 + 60 + 40 = 420.
The number of type B seedlings is 140.
Therefore, the probability of randomly selecting a type B plant is 140/420 = 1/3.
So, the probability is 1/3.
Company X tested its light bulbs to see how long they would last. On a production line, 2,500 bulbs were taken and tested. The department in charge reported that out of 2,500 bulbs, there were 2,200 bulbs that burnt out after more than 1,500 hours of use. Lucy purchased a light bulb from Company X. What is the likelihood that it will burn for more than 1,500 hours? Write your answer in decimal form.(1 point)
Out of the 2,500 bulbs tested, 2,200 bulbs burnt out after 1,500 hours of use.
Therefore, the likelihood that a light bulb from Company X will burn for more than 1,500 hours is 2,200/2,500 = 0.88.
So, the likelihood in decimal form is 0.88.
The letter tiles C , A , R , E , and S are placed in a box. Without looking, Jorelle picks a letter tile from the box and records the result before placing it back. He repeats the procedure 100 times and observes the following results:
Outcomes C A R E S
Frequency 20 25 30 10 15
Based on the observed frequency, what is the probability that Jorelle will pick a letter R ? The answer should be in percent form.
(1 point)
%
Based on the observed frequency, the number of times Jorelle picked the letter "R" is 30 out of 100 trials.
The probability of picking the letter "R" is 30/100 = 0.3 or 30%.
So, the probability that Jorelle will pick the letter "R" is 30%.
Use the table to answer the question.
Outcomes 2 4 6 8 10 12
Frequency 10 9 6 15 13 8
Jede tossed a cube with faces numbered with 2, 4, 6, 8, 10, and 12. The results are recorded in the table. What is the largest discrepancy between the experimental and the expected probability of this experiment? The answer needs to be in percent form to the nearest whole number.
To find the largest discrepancy between the experimental and expected probability, we first need to calculate the expected probability for each outcome based on a fair six-sided die:
Expected probability of getting 2, 4, 6, 8, 10, or 12 = 1/6 = 16.67%
Now, we compare the experimental frequency to the expected probability for each outcome:
- For 2: Experimental probability = 10/61 ≈ 16.39%
- For 4: Experimental probability = 9/61 ≈ 14.75%
- For 6: Experimental probability = 6/61 ≈ 9.84%
- For 8: Experimental probability = 15/61 ≈ 24.59%
- For 10: Experimental probability = 13/61 ≈ 21.31%
- For 12: Experimental probability = 8/61 ≈ 13.11%
The largest discrepancy is between the experimental probability of getting 8 (24.59%) and the expected probability (16.67%), which is 24.59% - 16.67% = 7.92%, rounded to the nearest whole number is 8%.
Therefore, the largest discrepancy between the experimental and expected probability in this experiment is 8%.
Use the table to answer the question.
Outcomes 2 4 6 8 10 12
Frequency 10 9 6 15 13 8
Jede tossed a cube with faces numbered with 2, 4, 6, 8, 10, and 12. The results are recorded in the table. What is the smallest discrepancy between the experimental and the expected probability of this experiment? Write your answer in 3 decimal places, rounded to the nearest thousandth.
To calculate the discrepancy between the experimental and expected probabilities for each outcome, we first need to determine the expected probability for each outcome based on a fair six-sided die:
The total number of outcomes in this experiment is 10 + 9 + 6 + 15 + 13 + 8 = 61.
Expected probability of getting 2, 4, 6, 8, 10, or 12 = 1/6 = 16.667%.
Now we compare the experimental frequency to the expected probability for each outcome and determine the discrepancies:
- For 2: Experimental probability = 10/61 ≈ 16.393%
- For 4: Experimental probability = 9/61 ≈ 14.754%
- For 6: Experimental probability = 6/61 ≈ 9.836%
- For 8: Experimental probability = 15/61 ≈ 24.590%
- For 10: Experimental probability = 13/61 ≈ 21.311%
- For 12: Experimental probability = 8/61 ≈ 13.115%
To find the smallest discrepancy, we will calculate the absolute differences between the experimental and expected probabilities for each outcome and find the smallest one:
Smallest discrepancy = |14.754% - 16.667%| = 1.913%
Therefore, the smallest discrepancy between the experimental and expected probabilities in this experiment is 1.913% or approximately 0.019.