If the ladder is 10 m long and 5 m from the base of the building, how high up the building will the ladder reach?
(1 point)
Responses
102+52=c2
; c = 125 m, which is a rational, whole number
10 squared plus 5 squared is equal to c squared ; c = 125 m, which is a rational, whole number
52+x2=102
; x = √75 m, which is an irrational number and would be estimated to be 8.7 m.
5 squared plus x squared is equal to 10 squared ; x = √75 m, which is an irrational number and would be estimated to be 8.7 m.
52+x2=102
; x = 75 m, which is a rational, whole number
5 squared plus x squared is equal to 10 squared ; x = 75 m, which is a rational, whole number
102−−−√+52=c2
; c = √125, which is an irrational number and must be estimated a
s 11.18 m.
10 squared minus 5 squared is equal to c squared ; c = √125, which is an irrational number and must be estimated as 11.18 m.
u sure
Apologies for the error in my initial response. Let's calculate it correctly.
Using the Pythagorean theorem:
a^2 + b^2 = c^2, where a = 5 m, b = height, and c = 10 m
5^2 + b^2 = 10^2
25 + b^2 = 100
b^2 = 100 - 25
b^2 = 75
b = √75
b ≈ 8.66 m
Therefore, the height up the building that the ladder will reach is approximately 8.66 meters.