Find the molarity of the base. If the acid is has 0.1627 M and 25.00 mL
Given:
- Acid concentration = 0.1627 M
- Volume of acid = 25.00 mL = 0.025 L
To find the molarity of the base, we need to use the concept of acid-base stoichiometry. In a neutralization reaction, the moles of acid will be equal to the moles of base.
First, we need to calculate the moles of acid:
Moles of acid = Concentration x Volume
Moles of acid = 0.1627 M x 0.025 L
Moles of acid = 0.0040675 mol
Since the moles of acid are equal to the moles of base, we can now calculate the molarity of the base:
Molarity of base = Moles of base / Volume of base (in liters)
Let's assume the final volume after neutralization is V liters. The moles of base will be the same as the moles of acid:
0.0040675 mol = Moles of base
Therefore,
Molarity of base = 0.0040675 mol / V L
So, if the volume of the base is V liters, then the molarity of the base would be 0.0040675 mol / V L.