A can is in the shape of a cylinder. The can has a volume of 450 cubic inches and a diameter of 4 inches. To the nearest tenth of an inch, what is the height of the can?(1 point)
Responses
11.8 in
143.2 in
35.8 in
9 in
9 in
explain how that is correct
To find the height of the can, we first need to calculate the radius of the can using the given diameter of 4 inches.
The formula for the volume of a cylinder is V = πr^2h, where V = volume, r = radius, and h = height.
Given that the volume V = 450 cubic inches and the diameter d = 4 inches, we can calculate the radius r as half of the diameter:
r = d/2 = 4/2 = 2 inches
Now, we have the volume V = 450 cubic inches, the radius r = 2 inches, and π
Substitute these values in the formula:
450 = π(2^2)h
450 = 4πh
h = 450 / (4π)
h ≈ 35.8 inches
Therefore, the height of the can is approximately 35.8 inches rounded to the nearest tenth of an inch.