what mass in grams of Na2 is required to react completely with 30.0 ml of 0,155M AgNO3?
To find the mass in grams of Na2 required to react completely with 30.0 ml of 0.155M AgNO3, we first need to determine the moles of AgNO3 present in 30.0 ml of 0.155M solution.
Moles of AgNO3 = Molarity x Volume (in L)
Moles of AgNO3 = 0.155 mol/L x 0.030 L
Moles of AgNO3 = 0.00465 mol
Since AgNO3 reacts with Na2 in a 1:2 molar ratio, we need twice as many moles of Na2 to react completely.
Moles of Na2 = 2 x Moles of AgNO3
Moles of Na2 = 2 x 0.00465 mol
Moles of Na2 = 0.00930 mol
Next, we need to find the molar mass of Na2. The molar mass of Na2 is 45.98 g/mol.
Mass of Na2 = Moles of Na2 x Molar Mass of Na2
Mass of Na2 = 0.00930 mol x 45.98 g/mol
Mass of Na2 = 0.427 g
Therefore, 0.427 grams of Na2 is required to react completely with 30.0 ml of 0.155M AgNO3.