I am to solve this system of equations x+3y=8
x=4-3y
I got (2,2), but I am not sure if this is righ, can you help me?
Try substituting (2, 2) into both equations to check if they hold.
It is possible for a system of equations to have no solution.
I am gathering there is no solution because in the second equation it would not be 2 it would be -2...am I right?
Yes.
You can rearrange the equations to get
x + 3y = 8
x + 3y = 4
In that form, there is obviously no solution.
To solve the system of equations, we can use the substitution method.
The first equation is x + 3y = 8, and the second equation is x = 4 - 3y.
To start, we will substitute the value of x from the second equation into the first equation.
Substituting x = 4 - 3y into x + 3y = 8, we get:
(4 - 3y) + 3y = 8
Simplifying, we have:
4 - 3y + 3y = 8
The -3y and +3y cancel each other out, so we are left with:
4 = 8
However, this is not a true statement. Therefore, there is no solution to this system of equations.
Hence, the solution (2, 2) is incorrect.