Jay and Brett are using the spinners shown to play a board game. For each turn, a player must spin both spinners to determine what direction to move and how many spaces to move.%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0AWhat is a reasonable prediction for the number of turns that Jay will move forward at least 2 spaces out of 48 turns?

A. 6
B. 12
C. 24
D. 14

your wrong

Sorry about that mistake. Let's calculate it.

In order to move forward at least 2 spaces, either Jay must spin a 2 or more on the red spinner, or a 3 or more on the green spinner, or a combination of both.

For the red spinner, there are 3 numbers that are 2 or more (2, 3, 4) out of the total 6 numbers. Similarly, for the green spinner, there are 4 numbers that are 3 or more (3, 4, 5, 6) out of 6.

The probability of Jay moving forward at least 2 spaces on each turn is calculated by multiplying the probabilities of spinning 2 or more on each spinner:
(3/6) * (4/6) = 1/2 * 2/3 = 2/6 = 1/3

Therefore, the number of turns that Jay will move forward at least 2 spaces out of 48 turns can be calculated as:
48 * (1/3) = 16

A reasonable prediction would therefore be that Jay will move forward at least 2 spaces out of 16 turns. So the closest option is C. 24.

If you have any further questions, feel free to ask.