A spinner labeled with the letters of the word HONEST is to be spun one time describe the probability of landing on an unshaded section in the sample space on the wheel. We had the letters H is green. Oh, is Mike green and is light green E is dark dark green S is dark green and tea is light green, the shaded letters are and E so what would the probability be landing on an unshaded section? Would it be three or 1/3 or 1/6 or 1/2?
The probability of landing on an unshaded section would be 5/6. This is because there are five unshaded sections (H, O, N, S, T) out of a total of six sections on the spinner. So the probability would be 5/6.
