solution was prepared by dissolving 1210 mg of K3Fe(CN)6 (329.2 g/mol) in sufficient water to give 577 mL. Calculate the molar concentration of K .
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0 points
42.1 ×10 -3 M K+
42.1 ×10+2 M K+
1.91 ×10 -2 M K+
42.1 ×10-2 M K+
To calculate the molar concentration of K in the solution, we need to first calculate the number of moles of K3Fe(CN)6 present in the solution.
Moles of K3Fe(CN)6 = 1210 mg / 329.2 g/mol
Moles of K3Fe(CN)6 = 0.003672 mol
Since there are three moles of K in one mole of K3Fe(CN)6, we can calculate the moles of K present in the solution:
Moles of K = 0.003672 mol x 3
Moles of K = 0.011016 mol
Now, we calculate the molar concentration of K:
Molar concentration of K = Moles of K / Volume of solution (in L)
Molar concentration of K = 0.011016 mol / 0.577 L
Molar concentration of K = 0.019092 M
Therefore, the molar concentration of K in the solution is 1.91 × 10^-2 M K+.
So, the correct answer is 1.91 × 10 -2 M K+.