( b)(8y^2−4y^4)=40y^4−20y^6 Solve for b
To solve for b, we need to isolate b on one side of the equation.
Given: b(8y^2 - 4y^4) = 40y^4 - 20y^6
First, distribute b to both terms inside the parentheses:
8by^2 - 4by^4 = 40y^4 - 20y^6
Rearrange the terms to isolate b:
8by^2 + 20y^6 = 40y^4 + 4by^4
Combine like terms:
8by^2 + 20y^6 = (40 + 4b)y^4
To solve for b, we can set the coefficients of y^4 on both sides equal to each other:
40 + 4b = 0
Subtract 40 from both sides:
4b = -40
Divide by 4:
b = -10
Therefore, the solution for b is -10.