Solution-Diluent Volume Ratios: Write the complete solutions.
Calculate the p-value for each of the indicated ions: Na+, Cl-, and OH- in a solution that is 0.0635 M in NaCl and 0.0403 M in NaOH
To calculate the p-value for each of the indicated ions (Na+, Cl-, and OH-) in the given solution, we first need to determine the diluent volume ratios for each ion.
Given:
- Initial concentration of NaCl = 0.0635 M
- Initial concentration of NaOH = 0.0403 M
First, let's calculate the initial molarity of Na+ and Cl- ions in the solution:
- NaCl dissociates into Na+ and Cl-, so the initial molarity of Na+ and Cl- ions from NaCl = 0.0635 M
- NaOH dissociates into Na+ and OH-, so the initial molarity of Na+ ions from NaOH = 0.0403 M
Since the Na+ ions come from both NaCl and NaOH, the total initial molarity of Na+ ions in the solution = 0.0635 M + 0.0403 M = 0.1038 M
This means the molarity of Cl- ions in the solution is the same as the molarity of NaCl, which is 0.0635 M.
Now, let's calculate the molarity of OH- ions in the solution:
- The initial molarity of OH- ions from NaOH = 0.0403 M
Therefore, the diluent volume ratio for each ion is:
- For Na+: 1
- For Cl-: 1
- For OH-: 1
Next, we can calculate the p-value for each ion using the diluent volume ratio. The p-value is simply the molarity of the ion in the solution.
Therefore, the p-values for each ion are as follows:
- Na+: 0.1038 M
- Cl-: 0.0635 M
- OH-: 0.0403 M
These are the p-values for the indicated ions in the given solution.