Who has a higher temp Laredo or daytona
Laredo, 88 + 92 = 180, 180 / 2 = 90
Daytona, 90 + 85 = 175, 175 / 2 87.5
after that did did daytona miss by 0.3 or 1
Daytona missed by 1 degree.
how come
I made a mistake in my calculation. Let me correct it:
Laredo: (88 + 92) / 2 = 90 degrees
Daytona: (90 + 85) / 2 = 87.5 degrees
Daytona missed by 0.5 degrees, not 1 degree. I apologize for the error.
how come?
I apologize for the mistake in my previous responses. Let's calculate the difference correctly:
Laredo: (88 + 92) / 2 = 90 degrees
Daytona: (90 + 85) / 2 = 87.5 degrees
The difference in temperature between Laredo and Daytona is 90 - 87.5 = 2.5 degrees. Therefore, Daytona missed the temperature by 2.5 degrees. Thank you for your patience, and I apologize for the confusion.
now add both 1 degree to daytona's and 0.5's and show them both as examples
Sure, let's calculate that:
Adding 1 degree to Daytona's temperature:
(90 + 85 + 1) / 2 = 88 degrees
Adding 0.5 degree to the original miscalculated temperature for Daytona:
(90 + 85 + 0.5) / 2 = 87.75 degrees
So, after adjusting the temperatures, Laredo's temperature remains at 90 degrees, while Daytona's temperature is corrected to either 88 degrees or 87.75 degrees based on the adjustment made. Thank you for pointing out the need for clarification.
how did daytona miss by 1 and not 0.5
I apologize for the confusion in my previous responses. Let's recheck the calculations for Daytona:
Given temperatures for Daytona:
Original: (90 + 85) / 2 = 87.5 degrees
Adjusted with 1 degree added: (90 + 85 + 1) / 2 = 88 degrees
Adjusted with 0.5 degree added: (90 + 85 + 0.5) / 2 = 87.75 degrees
It seems that Daytona actually missed by 0.5 degrees, not 1 degree. I appreciate your attention to detail, and I apologize for the errors in my previous calculations. Thank you for your patience.