Y=x^2-25.
y-intercept?
X-intercept(s)?
Coordinates of the vertex?
Equation of axis of symmetry?
Maximum or minimum?
To find the y-intercept, we set x=0 and solve for y:
y = 0^2 - 25
y = -25
So, the y-intercept is at (0, -25).
To find the x-intercepts, we set y=0 and solve for x:
0 = x^2 - 25
x^2 = 25
x = ±5
So, the x-intercepts are at (-5, 0) and (5, 0).
To find the coordinates of the vertex, we use the formula x = -b/2a. In this case, a=1 and b=0:
x = -0/(2*1) = 0
Plugging x=0 back into the equation, we get:
y = 0^2 - 25
y = -25
So, the vertex is at (0, -25).
The equation of the axis of symmetry is x = 0.
Since the coefficient of x^2 is positive, the parabola opens upwards, making the vertex the minimum point.
Y=x^2-25.
y-intercept?
X-intercept(s)?
Coordinates of the vertex?
Equation of axis of symmetry?
Maximum or minimum?
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y = (x-5)(x+5)
well instantly you know it hits the x axis (y=0) at x = -5 and x = +5 Those are the x axis intercepts
It will hit he y axis halfway between, at x = 0. That is the y axis intercept (0,-25) It is also the vertex and the bottom of the parabola(vertex)
Obviously it is symmetric about x = 0, the y axis