According to one study, 61% of the population swallow at least one spider per year in their sleep. Based on this study, what is the probability that exactly 7 of 10 randomly selected people have swallowed at least one spider in their sleep in the last year.
(1 point)
Responses
70%
70%
22%
22%
1%
1%
34%
1%
To calculate this probability, we can use the binomial probability formula:
P(x) = (n choose x) * p^x * (1-p)^(n-x),
where n = 10 (number of trials), x = 7 (number of successes), p = 0.61 (probability of success).
Plugging in these values, we get:
P(7) = (10 choose 7) * (0.61)^7 * (1-0.61)^(10-7)
P(7) = 120 * (0.61)^7 * (0.39)^3
P(7) ā 0.009
Converting this to a percentage, we get approximately 0.9%, which is closest to 1%.