Example 1.Express the concentration of 315 mL of solution containing 10.3 g of isopropyl alcohol, C3H7OH in molarity (M).
To calculate the molarity of the solution, we first need to determine the moles of isopropyl alcohol present in the solution.
Step 1: Convert grams of isopropyl alcohol to moles.
Molar mass of isopropyl alcohol (C3H7OH) = 60.1 g/mol
10.3 g / 60.1 g/mol = 0.171 moles
Step 2: Calculate molarity.
Molarity (M) = moles of solute / volume of solution in liters
Volume of solution = 315 mL = 0.315 L
Molarity (M) = 0.171 moles / 0.315 L = 0.543 M
Therefore, the concentration of the solution containing 10.3 g of isopropyl alcohol in 315 mL is 0.543 M.