y = –6.8x + 8.3; y = x^2 – 3.2x + 10.1
what are the solutions to the system of equations?
a.(–0.60, 12.38) and (–3, 28.7) (–0.60, 12.38) and (–3, 28.7) b.(–0.60, 28.7) and (–3, 12.38) (–0.60, 28.7) and (–3, 12.38) c.(–0.60, 12.38) and (3, –12.1) (–0.60, 12.38) and (3, –12.1) d.There is no solution.???
Using the substitution method, we can set the two equations equal to each other:
-6.8x + 8.3 = x^2 - 3.2x + 10.1
Rearranging terms, we get:
x^2 - 7.6x + 2.3 = 0
Solving this quadratic equation, we get:
x = -0.60 or x = 3
Plugging these x values back into one of the original equations (let's use y = –6.8x + 8.3), we find the corresponding y values:
For x = -0.60: y = –6.8(-0.60) + 8.3 = 12.38
For x = 3: y = –6.8(3) + 8.3 = -12.1
Therefore, the solutions to the systems of equations are (-0.60, 12.38) and (3, -12.1), which corresponds to option c. (-0.60, 12.38) and (3, -12.1).
which one is it
Apologies for the confusion earlier. The correct solutions to the system of equations are:
c. (-0.60, 12.38) and (3, -12.1)
earlier you said it was b and a
I apologize for the confusion in my responses earlier. Let me clarify:
The correct solutions to the system of equations y = –6.8x + 8.3 and y = x^2 – 3.2x + 10.1 are:
c. (-0.60, 12.38) and (3, -12.1)
Thank you for pointing out the error, and I appreciate your understanding.
so what is the answer?
Apologies for the confusion in my responses. The correct solutions to the system of equations are:
c. (-0.60, 12.38) and (3, -12.1)
Thank you for your patience.
y = –6.8x + 8.3; y = x^2 – 3.2x + 10.1
what are the solutions to the system of equations?
a.(–0.60, 12.38) and (–3, 28.7) (–0.60, 12.38) and (–3, 28.7) b.(–0.60, 28.7) and (–3, 12.38) (–0.60, 28.7) and (–3, 12.38) c.(–0.60, 12.38) and (3, –12.1) (–0.60, 12.38) and (3, –12.1) d.There is no solution.
The correct solutions to the system of equations are:
c. (-0.60, 12.38) and (3, -12.1)