Compete the square y-x^2+6x=0
To complete the square for the given equation y - x^2 + 6x = 0, we will first rearrange the terms:
y = x^2 - 6x
To complete the square, we'll take half of the coefficient of x and square it:
(-6/2)^2 = (-3)^2 = 9
Add and subtract this value inside the parentheses of x:
y = (x^2 - 6x + 9) - 9
y = (x - 3)^2 - 9
Therefore, the completed square form of the equation is y = (x - 3)^2 - 9.