A big flower vase has 5 begonias, 6 carnations, and 7 tulips. Two flowers are randomly selected without replacement. What is the probability of selecting two carnations? Express the answer in the simplest form of fraction.(1 point)
The total number of flowers in the vase is 5 + 6 + 7 = 18.
The probability of selecting a carnation on the first pick is 6/18 = 1/3.
After selecting a carnation on the first pick, there are now only 17 flowers in the vase, with 5 begonias, 5 carnations, and 7 tulips left.
The probability of selecting a carnation on the second pick is 5/17.
Therefore, the overall probability of selecting two carnations is:
(1/3) * (5/17) = 5/51
So, the probability of selecting two carnations is 5/51.