Convert a pOH value of 9.95 to [OH-].
To convert pOH to [OH-], you can use the formula:
[OH-] = 10^(-pOH)
So, for a pOH value of 9.95:
[OH-] = 10^(-9.95)
[OH-] = 1.12 x 10^(-10)
Therefore, the concentration of hydroxide ions ([OH-]) corresponding to a pOH value of 9.95 is 1.12 x 10^(-10) M.