Solve the system of equations Using elimination with multiplication
4x-6y=-48
-2x+4y=30
To solve this system of equations using elimination with multiplication, we need to manipulate the equations so that we can add them together and eliminate one of the variables.
First, we can manipulate the second equation by multiplying both sides by 2 to eliminate the x-terms:
-2x + 4y = 30
(2)*(-2x + 4y) = (2)*(30)
-4x + 8y = 60
Now, we have the system of equations:
4x - 6y = -48
-4x + 8y = 60
Adding the two equations together, we get:
4x - 6y + (-4x + 8y) = -48 + 60
2y = 12
y = 6
Now that we have found the value of y, we can substitute it back into one of the original equations to solve for x. Let's use the first equation:
4x - 6(6) = -48
4x - 36 = -48
4x = -12
x = -3
Therefore, the solution to the system of equations is x = -3 and y = 6.