The path of a rocket ship is given by the parametric equations x(t)=3t and y(t)=4t^2+1, where t is the time in seconds after launch. Where is the ship after 10 seconds?
A. (3,4)
B. (3,5)
C. (30,401)
D. (30,501)
To find the position of the rocket ship after 10 seconds, we need to substitute t=10 into the parametric equations x(t) and y(t):
x(10) = 3(10) = 30
y(10) = 4(10)^2 + 1 = 4(100) + 1 = 401
Therefore, the rocket ship is at position (30, 401) after 10 seconds. So, the correct answer is C. (30,401).