Two forces act on a 4.5 kg block resting on a frictionless surface as shown in the Figure. What is the magnitude of the horizontal acceleration of the block? Applied force at 3,7 N, Horizontal force at 5,9 N At Angle 43
3.2 m/s2
1.8 m/s2
1.8 m/s2
1.2 m/s?
To find the horizontal acceleration of the block, we need to analyze the forces acting on it.
The applied force of 3.7 N can be resolved into horizontal and vertical components using trigonometry. The horizontal component is given by 3.7 N * cos(43°) = 2.64 N.
The horizontal component of the applied force is in the positive direction, while the horizontal force of 5.9 N is in the negative direction. The net horizontal force acting on the block is 2.64 N - 5.9 N = -3.26 N.
Now, we can use Newton's second law to find the acceleration of the block. The net force is equal to the mass of the block times its acceleration:
F = m*a
-3.26 N = 4.5 kg * a
a = -3.26 N / 4.5 kg
a = -0.724 m/s^2
Since the acceleration is negative, it means the block is accelerating in the negative direction. The magnitude of the acceleration is 0.724 m/s^2. So, the correct answer is 0.724 m/s^2.