Integration (solve)
X^-3(x+1)dx
To solve this integral, we first need to simplify the expression by expanding the term (x+1) with X^-3.
X^-3(x+1) = X^-3 * x + X^-3 * 1
= X^-2 + X^-3
Now, we can rewrite the integral as:
∫(X^-2 + X^-3)dx
Now, we can integrate each term separately.
∫X^-2 dx = (1/-1)X^-1 + C = -X^-1 + C
∫X^-3 dx = (1/-2)X^-2 + C = -1/2X^-2 + C
Therefore, the final result of the integration is:
∫(X^-2 + X^-3)dx = -X^-1 - 1/2X^-2 + C
where C is the constant of integration.