Integration (solve)
S=x^-3(x+1)dx
To solve the integration of S=x^-3(x+1)dx, we need to expand the expression and then integrate each term individually.
First, expand the expression:
S = x^-3 * x + x^-3 * 1
S = x^-2 + x^-3
Now, integrate each term:
∫(x^-2)dx = x^-1 / -1 = -x^-1
∫(x^-3)dx = x^-2 / -2 = -1/2*x^-2
Therefore, the final result for the integration of S=x^-3(x+1)dx will be:
S = -x^-1 - 1/2*x^-2 + C
where C is the constant of integration.