find the value of x.
triangle xyz 2x, 4x+1, and 2x+3
perimeter of triangle xyz=88
To find the value of x in the triangle XYZ, we can use the perimeter equation.
The perimeter of a triangle is the sum of the lengths of its three sides.
In this case, the sides of triangle XYZ are given as:
Side XY = 2x
Side YZ = 4x + 1
Side ZX = 2x + 3
To find the perimeter, we add up these three side lengths:
2x + (4x + 1) + (2x + 3) = 88
Now, let's solve the equation for x:
2x + 4x + 1 + 2x + 3 = 88
Combining like terms:
8x + 4 = 88
Subtracting 4 from both sides:
8x = 84
Dividing both sides by 8:
x = 10.5
Therefore, the value of x is 10.5.
perimeter= sum of sides
88=2x + 4x+1 + 2x+3
solve for x.