Solve the system of equations negative 6X plus 2Y equals -32 and 4X plus 3Y equals -9
To solve this system of equations, we will use the method of elimination.
Given equations:
-6X + 2Y = -32 (1)
4X + 3Y = -9 (2)
First, multiply equation (1) by 2 to get:
-12X + 4Y = -64 (3)
Now, we will add equation (3) and equation (2) to eliminate X:
-12X + 4Y + 4X + 3Y = -64 - 9
-8X + 7Y = -73
Now, we have a new equation: -8X + 7Y = -73 (4)
Now, we can solve this equation along with equation (1):
-6X + 2Y = -32
-8X + 7Y = -73
Now, multiply equation (1) by 4 and equation (2) by 3:
-24X + 8Y = -128 (5)
12X + 9Y = -27 (6)
Add equations (5) and (6) to eliminate X:
-24X + 8Y + 12X + 9Y = -128 - 27
-12X + 17Y = -155
Now, we have a new equation: -12X + 17Y = -155 (7)
Now, we have 2 equations:
-8X + 7Y = -73 (4)
-12X + 17Y = -155 (7)
Now, we can solve this system of equations using any method such as elimination or substitution to find the values of X and Y.