On a standardized exam, the scores are normally distributed with a mean of 400 and a standard deviation of 25. Find the z-score of a person who scored 325 on the exam.
To find the z-score of a person who scored 325 on the exam, we can use the formula:
z = (X - μ) / σ
where:
X = the score (325)
μ = the mean (400)
σ = the standard deviation (25)
Plugging in the values:
z = (325 - 400) / 25
z = -75 / 25
z = -3
Therefore, the z-score of a person who scored 325 on the exam is -3.