Two containers designed to hold water are side by side by side both in a cylinder shape. Container a has a radius of 3 feet and a height of 5 feet.Container B has a radius of 2 feet and a height of 15 feet. Container a is pumped into container b until Empty. After the pumping is complete what is the volume of the empty portion of Container B, to the nearest tenth of a cubic foot?
First, we need to calculate the volume of water held in Container A and Container B.
Volume of Container A:
V = πr²h
V = π(3)²(5)
V = 45π cubic feet
Volume of Container B:
V = πr²h
V = π(2)²(15)
V = 60π cubic feet
Since Container A is pumped into Container B until empty, the total volume of water in Container A will be transferred to Container B. The volume of the empty portion of Container B after the transfer is completed can be calculated as:
Empty portion of Container B = Volume of Container B - Volume of water from Container A
Empty portion of Container B = 60π - 45π
Empty portion of Container B = 15π ≈ 47.1 cubic feet
Therefore, the volume of the empty portion of Container B, to the nearest tenth of a cubic foot, is approximately 47.1 cubic feet.