What is the diameter of a sphere with a volume of
616ft cubed to the nearest tenth of a foot?
The formula for the volume of a sphere is V = (4/3)πr^3, where r is the radius of the sphere.
Since we are given the volume as 616 ft^3, we can rearrange the formula to solve for the radius:
616 = (4/3)πr^3
r^3 = 3/4 * 616 / π
r^3 = 462 / π
r = (462 / π)^(1/3)
Using a calculator, we find r ≈ 6.5 ft
The diameter of a sphere is twice the radius, so the diameter is 2 * 6.5 = 13 ft
Therefore, the diameter of a sphere with a volume of 616 ft^3 is approximately 13 ft.