What is the surface area of a rectangular prism whose dimensions are 3 3/4 dm×4 1/2 dm×5 dm in square decimeters?(1 point)Responses11614 dm2116 Start Fraction 1 over 4 End Fraction dm squared84 3/8 dm2 8/4 Start Fraction 3 over 8 End Fraction dm squared16 dm216 dm squared581/8 8 dm2
The surface area of a rectangular prism can be calculated using the formula:
Surface Area = 2lw + 2lh + 2wh
Given dimensions:
Length (l) = 3 3/4 dm = 15/4 dm
Width (w) = 4 1/2 dm = 9/2 dm
Height (h) = 5 dm
Plugging the values into the formula:
Surface Area = 2(15/4 * 9/2) + 2(15/4 * 5) + 2(9/2 * 5)
Surface Area = 2(135/8) + 2(75/4) + 2(45/2)
Surface Area = 270/8 + 150/4 + 90/2
Surface Area = 33.75 + 37.5 + 45
Surface Area = 116.25 square decimeters
Therefore, the surface area of the rectangular prism is 116.25 square decimeters.
Response: 116.25 dm^2