Triangle ABC has vertices points A (-2,-2), point B (-4,-3), and point C (-2,-5). Find the coordinates of A'B'C' after a dilation with a scale of factor of 3 and a center point of dilation at the origin
To find the coordinates of A'B'C' after a dilation with a scale factor of 3 and a center point of dilation at the origin, we can use the following formula:
A'(x', y') = (3x, 3y)
First, we find the coordinates of A'B'C':
A' = (3(-2), 3(-2)) = (-6, -6)
B' = (3(-4), 3(-3)) = (-12, -9)
C' = (3(-2), 3(-5)) = (-6, -15)
Therefore, the coordinates of the vertices of triangle A'B'C' after the dilation are:
A' (-6, -6)
B' (-12, -9)
C' (-6, -15)