The Maynard High School boosters are selling hot dogs and pretzels at the concession stand they have $300 hot dogs and pretzels in stock and want to earn an income of $800 they plan to sell the hot dogs for $4 each and the pretzels for $2 each how many hot dogs and how many pretzels do the boosters need to sell to reach their goal of 800
Let x be the number of hot dogs sold and y be the number of pretzels sold.
The total income from selling hot dogs is 4x and the total income from selling pretzels is 2y.
The boosters want to earn a total income of $800, so we can write the equation:
4x + 2y = 800
They have $300 worth of hot dogs and pretzels in stock, so we can also write the equation:
x + y = 300
Now we have a system of two equations:
4x + 2y = 800
x + y = 300
To solve this system, we can multiply the second equation by 2 and subtract it from the first equation to eliminate y:
4x + 2y - 2x - 2y = 800 - 600
2x = 200
x = 100
Now plug x = 100 back into the second equation to solve for y:
100 + y = 300
y = 200
So, the boosters need to sell 100 hot dogs and 200 pretzels to reach their goal of $800.