Describe the vertical asymptote(s) and hole(s) for the graph of y = x minus six over x squared plus five times x plus six.
(1 point)
The vertical asymptotes for the graph of the function y = (x-6)/(x^2 + 5x + 6) occur at x = -1 and x = -6, where the denominator equals zero.
There is a hole at x = -6, since both the numerator and the denominator have a factor of (x+6), which cancel out at that point.